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Annual production of 15000m³ of plywood production line
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Annual production of 15000m³ of plywood production line

Views: 0     Author: SHANDONG MINGHUNG WOOD MACHINERY CO.,LTD     Publish Time: 2022-11-16      Origin: MINGHUNG PLYWOOD MACHINE

Annual production of 15000m³ of plywood production line

Annual output: 15000m3/year

Product specification: 1220×2440×3mm 60%

1220×2440×11mm 40%

Tree species: poplar 40%, colored wood 20%, ash 20%, teak 20%;

Glue type: infiltrating tree adhesive;

Log specifications: Length: 6m;

Average straight line: 420mm;

Gluing method: dry heat method

Working system: 280 days/year, two shifts, 8 hours per shift;

Design requirements: determine the production process between vehicles;

Calculate the raw and auxiliary material requirements of the product;

Select production equipment and calculate the number of equipment units (sets);

Calculate the number of people required in the vehicle room;

Floor plan of workshop equipment;

SHANDONG MINGHUNG WOOD MACHINERY CO.,LTD

Calculation process and description

一、Calculate the species and percentage of each species: 

Tree species:  Poplar、pine、birch、Eucalyptus、Beech,ect.

Specification: 1220*2440*3mm/1220*2440*5mm

layer: 5/11layer

二、Calculate hot press production capacity:

Total pressure (t): 500/600/8001000tons; Number of hot platen layers: 20layers; Height of hot platen spacing: 70mm

Heating medium: saturated steam/heat transfer oil; Board installation direction: narrow side board; Total motor power: 29.5kw//41kw/56kw

Hot plate size: 2700×1370×42mm/2700×1370×52mm/2700*1900*52mm/1400*1400*52mm; manufacturer: MINGHUNG WOOD MACHINERY

Separate calculations of press productivity for the production of various types of plywood:

(1) Separately calculate the production rate of presses for producing various plywood, the production rate Q (m3/shift) can use the following formula Q=F×s×m×n×T×K/1000(Z1+Z2):

T-----working time per shift, 480min;

n ----- the number of working intervals of the press, n=20;

m-----The number of sheets of plywood installed in each interval (three layers m=1, eleven layers m=1)

s ------ plywood thickness (: 3mm, : 5mm)

F-----Plywood area 1220×2440=2.9768m2

Z1----pressing time in the press (three layers: Z1=3min; eleven layers: Z1=11min;)

Z2-----Auxiliary operation time takes 1.5min

K-----Working time utilization coefficient k=0.96

3mm plywood : Q1=18.10m3/shift

Poplar Q1=480×20×1×3×2.9768×0.96/[1000(3+1.5)]=18.10m3/class

pine Q1=480×20×1×3×2.9768×0.96/[1000(3+1.5)]=18.10 m3/shift

birch Q1=480×20×1×3×2.9768×0.96/[1000(3+1.5)]=18.10 m3/class

Eucalyptus Q1=480×20×1×3×2.9768×0.96/[1000(3+1.5)]=18.10 m3/shift

Beech Q1=480×20×1×3×2.9768×0.96/[1000(3+1.5)]=18.10 m3/shift

5mm plywood : Q2=23.88m3/shift

Poplar Q2=480×20×1×11×2.9768×0.96/1000 (11+1.5)=23.88m3/shift

pine Q2=480×20×1×11×2.9768×0.96/1000 (11+1.5)=23.88m3/shift

birch Q2=480×20×1×11×2.9768×0.96/1000 (11+1.5)=23.88m3/class

Eucalyptus Q2=480×20×1×11×2.9768×0.96/1000 (11+1.5)=23.88m3/shift

Beech Q2=480×20×1×11×2.9768×0.96/1000 (11+1.5)=23.88m3/shift

(2) Weighted average productivity of the hot press Qp=100/(a1/Q1+a2/Q2): 

Qp: weighted average production capacity of hot press;

Q1, Q2: The output of various plywood single output of hot press;

a1, a2 The percentages specified for various plywood %, then:

Qp=100/(60/18.10+40/23.88)=20.04m3/shift

(3) Productivity of hot press machine in each shift in actual production: Q΄=15000×1.1/(280×2)=29.46 m3/shift

15000------annual output, m3;

280------Number of working days per year, days;

2------Number of working shifts per day;

1.1-----Reserved amount of doubtful project shall take 10% of annual output.

(4) Calculation of the number of hot presses n=2 η=77%

n=29.46/20.04=1.47 units, take 2 units

Load rate η=0=1.47/2×100%=77%

三. Compile the block diagram of the production process

Log Storage→ Log Cutting→ Segment Cooking→ Segment Stripping→ Segment Centering→veneer peeling →veneer drying →sorting and grading Veneer shearing→

→Gluing Veneer→Blank assembly→ cold pressing→hot pressing,→edge trimming→plywood sanding→inspection and grading→packaging and warehousing.

四. Calculation of raw material requirements

(1) Calculation of the quantity of finished products put into the warehouse QQ=QC - QC ×a/100= QC(1-a/100)

QC ----- production capacity of hot press machine shift, 29.46m3/shift;

a --------Consumption in the plywood factory takes a=4%;

Q------the quantity of finished products put into the warehouse, m3/shift;

Then Q=29.46×(1-4/100)=28.28 m3/shift

Amount of plywood consumed:

q1=QC-Q=29.46-28.28=1.18m3/shift;

Quantity of plywood consumed per m3 finished product:

q10=a/(100-a)=0.042 m3/shift.

Yield rate of finished plywood: q1=1.18 m3/shift q10=0.042 m3/shift

p1= Q / QC.×100%=28.28/29.46×100%=96.0%;

The quantity p1= QC/Q=100/(100-a)=1.042 m3/shift for every m3 of finished plywood.

(2) Quantity calculation of uncut plywood aC = (FW –FC )/FW×100% =11.2%

FW ----- Uncut plywood area m3, FW = (1.22+0.1) × (2.44+0.1);

FC------cut edge plywood area m3, FC=2.9768;

aC-------The trimming consumption percentage of the board.

Untrimmed plywood quantity calculation:

QW= FW /FC ×[100/(100-a)]×Q; that is, QW=33.19 m 3 /shift

Amount of waste from trimming: q2=Qc[(FW /FC)-1]=3.72 m3/class

Amount of scrap per m3 finished product: q2°=100/(100-a)×FW /(FC-1)=0.13m3/shift

Yield from uncut plywood to trimmed plywood: p2 =Fc/Fw×100%=88.79%

The quantity R2 of uncut plywood per m3 of finished plywood is: R2= QW /Q=Fc /Fw×(100-a)= 1.048m3

(3) Calculation of the required amount of dry veneer

The quantity of dry veneer depends on the compression rate ay calculated with the following formula: ay=(Sw-Si)/Sw×100%

Sw ----- total thickness of the uncompressed veneer in the slab: 5 layers 3.3mm; 11 layers 12.1mm;

Si------ Finished plywood thickness: 3.3mm for 5 layers; 12.1mm for 11 layers;

Then 5layers ay=(3.3-5)/3.3×100%=9.1%

11 layers ay=(12.1-11)/12.1×100%=9.1%

Calculation of dry veneer quantity: Qg=Qw×100(100-ay)


1220×2440×5

1220×2440×11

Then the total consumption is q3=4.22 m3/shift

The consumption of compression is q30 per m3 of finished plywood

q30=q3/Q=4.22/29.46=0.1432m3/shift

The yield rate from veneer to finished plywood p3=Q/Qg×100%=28.3/42.19×100%=67.08%

Quantity p3 of dry veneer consumed per m3 of finished plywood

R3=Qg/Q=1.491m3/shift

The quantity of dry veneer consumed per m3 of finished plywood should be 4% more than the above quantity:

Actual plywood consumes the number of dry veneers

p3'=1.491×(1+4%)=1.55m3/shift

(4) Calculation of wet veneer requirements 

When the veneer is dried, the excess waste and a part of the veneer that will be consumed during gluing, this part of the loss ah; take ah=4%

The number of dry veneers coming out of the dryer

Qgd=100/(100-ah)×Qg

1220×2440×5    23.6m³


1220×2440×11   20.36

wet veneer requirement

Qs=Qgd×100/(100-ag)

In the formula: the drying shrinkage loss on the width of the 

ag veneer is 12% for pine, 10% for poplar, 12% for beech, and 12% for birch.

Wet veneer requires total metering Qs= 46.66m3/shift

Non-recoverable loss caused by drying shrinkage:

q4=Qs-Qsg=46.66-43.96=2.7m3/shift

The yield p4 from wet veneer to finished plywood is: p4=Q/Qs×100%=29.46/46.66×100%=63.14%

Wet veneer loss per m3 of finished plywood

R4=Qs/Q=100/73.69=1.584m3/m3

(5) Calculation of log requirements

The length of the wood section required: 

The length of the wood section of the backboard in the table is 2440+70=2510mm

The length of core wood section 1220+50=1270mm

(A) The effective yield rate Vd of a wood veneer is: Vd=L/104 (k1×dm2-k2×dm-0.75ds2)

In the formula: Vd ------ the number of wet veneers that can be obtained by rotary cutting a piece of wood

dm -----The average diameter of the wood section is 260cm

L ------- wooden section length 6m

ds ------ wood core diameter 5.5cm k1, k2 coefficient:

For example, a piece of plywood has the following types of wood:

Poplar k1 =0.75, k2 =1.2 Ash k1 =0.73, k2 =1.25

Color wood k1 =0.73, k2 =1.25 Basswood k1 =0.73, k2 =1.25

When the length of wood section is 2510mm,

Poplar Vd1=2.51/106 (0.75×4202-1.2×420-0.75×552)=0.325m3

Ash Vd2=2.51/106 (0.73×2602-1.25×260-0.75×552)=0.316m3

Color wood Vd2=2.51/106 (0.73×2602-1.25×260-0.75×552)=0.316m3

Basswood Vd2=2.51/106 (0.73×2602-1.25×260-0.75×552)=0.316m3

When the length of wood section is 1270mm

Poplar: Vd3=1.27/106 (0.75×4202-1.2×420-0.75×552)=0.164m3

Ash Vd4=1.27/106 (0.73×2602-1.25×260-0.75×552)=0.160m3

Color wood Vd4=1.27/106 (0.73×2602-1.25×260-0.75×552)=0.160m3

Basswood Vd4=1.27/106 (0.73×2602-1.25×260-0.75×552)=0.160m3

B)Fragment material produced when wood segments are rounded: Vb=Vm-Vs-Vd

In the formula: Vs--wood core volume; Vm--wood section volume; Vd--effective yield rate of a wood section;

For example, when a piece of plywood has the following wood combinations:

When L=2.51m, Poplar: Vb1= 0.348-0.00596-0.325=0.01679m3

Ash: Vb2= 0.348-0.00596-0.316=0.02579 m3

Color wood: Vb2= 0.348-0.00596-0.316=0.02579 m3

Basswood: Vb2= 0.348-0.00596-0.316=0.02579 m3

When L=1.27m Poplar: Vb3= 0.176-0.00596-0.164=0.00599m3

Ash: Vb4= 0.176-0.00596-0.160=0.00999 m3

Color wood: Vb4= 0.176-0.00596-0.160=0.00999m3

Basswood: Vb4= 0.176-0.00596-0.160=0.00999 m3

C)The veneer output volume V of a piece of wood: V=Vd+Vb×100×N

For example, when a piece of plywood is composed of the following types of wood

When L=2.51m, Poplar: V1=0.325+0.01679×0.2=0.328358m3

Ash: V2= 0.316+0.02579×0.2=0.32116m3

Color wood: V2= 0.316+0.02579×0.2=0.32116m3

Basswood: V2= 0.316+0.02579×0.2=0.32116m3

When L=1.27m, Poplar: V3= 0.164+0.00599×0.2=0.165198m3

Ash: V4= 0.160+0.00999×0.2=0.162m3

Color wood: V4= 0.160+0.00999×0.2=0.162m3

Basswood: V4= 0.160+0.00999×0.2=0.162m3

Total V=1.943m3

D)Timber Requirements

Number of wood segments Nm=Qs/V

In the formula: Qs---the required wet veneer volume m3; V------the output rate of a wood section

For example, when a plywood is composed of the following logs:

1220×2440×5 Ash: L=2.51m, Nm1=(3.94×2/3)/0.32116=9 roots

Color wood: L=2.51 meters, Nm1=(3.94×2/3)/0.32116=9 pieces

Basswood: When L=2.51m, Nm1=(3.94×2/3)/0.32116=9 pieces

Poplar: When L=2.51 meters, Nm2=(14.66×2/3)/0.328358=30

Fraxinus mandshurica: when L=1.27 meters, Nm1'=(3.94×1/3)/0.162=9 roots

Color wood: L=1.27 meters, Nm1=(3.94×1/3)/0.162=9 pieces

Basswood: When L=1.27m, Nm1=(3.94×1/3)/0.162=9 pieces

Poplar: When L=1.27m, Nm2'=(14.66×1/3)/0.165198=30

1220×2440×11

Ash: L=2.51m, Nm3=(3.94×6/11)/0.32116=7 roots

Color wood: L=2.51 meters, Nm3=(3.94×6/11)/0.32116=7 pieces

Basswood: When L=2.51m, Nm3=(3.94×6/11)/0.32116=7 pieces

Poplar: When L=2.51 meters, Nm4=(14.66×7/11)/0.328358=29

Fraxinus mandshurica: when L=1.27 meters, Nm3'=(3.94×6/11)/0.162=14 roots

Color wood: when L=1.27 meters, Nm3'=(3.94×6/11)/0.162=14 pieces

Basswood: When L=1.27m, Nm3'=(3.94×6/11)/0.162=14 pieces

Poplar: When L=1.27m, Nm4'=(14.66×7/11)/0.165198=57

E)For example, when a piece of plywood is combined with the following types of wood Then the total log length is required:

When L=2.51m, 

Fraxinus mandshurica: 9+7=16 roots

Color wood: 9+7=16

Basswood: 9+7=16

Poplar: 30+29=59 roots

When L=1.27m,

 Ash: 9+14=23 roots

Color wood: 9+14=23

Basswood: 9+14=23

Poplar: 30+57=87 roots

(F)For example, when using the following wood combinations for a check:

Timber volume Qm: When L=2.51m, 

Ash: Qm1=16×0.348=5.568m3

Color wood: Qm1=16×0.348=5.568m3

Basswood: Qm1=16×0.348=5.568m3

Poplar: Qm2=59×0.348=20.532m3

When L=1.27m, 

Ash: Qm3=23×0.176=4.048m3

Color wood: Qm3=23×0.176=4.048m3

Basswood: Qm3=23×0.176=4.048m3,

Poplar: Qm4=87×.0.176=15.312m3

Total Qm=64.692m3


For example, when plywood uses the following wood combinations: The amount of waste q5 generated during rotary cutting of wood segments is:

When L=2.51m, Ash: q5=(0.348-0.32116)×16=0.43m3

Color wood: q5=(0.348-0.32116)×16=0.43m3

Basswood: q5=(0.348-0.32116)×16=0.43m3

Poplar: q5=(0.348-0.328358)×59=1.16m3

When L=1.27m, Ash: q5=(0.176-0.162)×23=0.32m3

Color wood: q5=(0.176-0.162)×23=0.32m3

Basswood: q5=(0.176-0.162)×23=0.32m3

Poplar: q5=(0.176-0.165198)×87=0.94m3

The total amount of waste q5 total = 4.35 m3

The amount of waste per m3 of finished plywood q50=q5/Q=0.148m3/m3

For example a piece of plywood when using the following wood combinations:

The amount of waste p5 from wood section to wet veneer is: p5=V/Vm×100%

When L=2.51m, Ash: p51=0.1125/0.1348×100%=83.46%

Poplar: p52=0.1109/0.1348×100%=82.27%

Ash: p51=0.1109/0.1348×100%=83.46%

Poplar: p52=0.1109/0.1348×100%=82.27%

When L=1.27m, Ash: p53=0.0584/0.070×100%=83.43%

Poplar: p54=0.0576/0.070×100%=82.29%

Poplar: p54=0.0576/0.070×100%=82.29%

Poplar: p54=0.0576/0.070×100%=82.29%

Then the yield p5' from the wood section to the wet veneer is: p5'=Q/Qm×100%=28.3/64.692×100%=43.74%

The wood section consumption p5 per m3 of plywood is: p5=100/p5'=100/45.54=2.29m3/m3

For example, when a piece of plywood uses the following wood combinations: determine the required quantity of logs Qy

Qy=100Qm/(100-ar) In the formula: ar is considering the loss of the flute field (log truncation rate): Determine ar=2%---4%, take ar= 4%

Q y=100×64.692/(100-4)=67.39 m3


The yield p6 from log to wood section is: p6=Q m/Q y×100%=64.692/67.39×100%=96%;

The log requirement R6 per m³ of finished plywood is: R6= Q y total / Q=67.39/28.3=2.38m³/ m³;

The output rate p61 from log to finished plywood is: p61= Q / Q y total × 100% = 41.99%;

G

Determine the quantity Qy of logs required

Qy=100Qm/(100-ar) In the formula: ar is considering the loss of the flute field (log truncation rate):Determine ar=2%---4%, take ar= 4%

Q y=100×64.692/(100-4)=67.39 m3


The yield p6 from log to wood section is: p6=Q m/Q y×100%=64.692/67.39×100%=96%;

The log requirement R6 per m³ of finished plywood is: R6= Q y total / Q=67.39/28.3=2.38m³/ m³;

The output rate p61 from log to finished plywood is: p61= Q / Q y total × 100% = 41.99%;

H)When plywood uses the following wood combinations: Unutilized wood core volume:

When L=2.51 m,

Ash: V1=3.14×0.0552/4×2.51×16=0.095m³/shift;

Color wood: V1=3.14×0.0552/4×2.51×16=0.095m³/class;

Basswood: V1=3.14×0.0552/4×2.51×16=0.095m³/class;

Poplar: V2=3.14×0.0552/4×2.51×59=0.352m³/class;

When L=1.27m,

Ash: V3=3.14×0.0552/4×1.27×23=0.069m³/shift;

Poplar: V4=3.14×0.0552/4×1.27×87=0.263 m³/class;

Ash: V3=3.14×0.0552/4×1.27×23=0.069m³/shift;

Poplar: V4=3.14×0.0552/4×1.27×87=0.263 m³/class

V=0.352+0.095×3+0.263+0.06923=1.107m³/shift;

I

Unutilized chipped material volume when plywood uses the following wood combinations:

When L=2.51 m,

Ash: V1=0.02579×0.8×16=0.3301 m³/class;

Color wood: V1=0.02579×0.8×16=0.3301 m³/class;

Basswood: V1=0.02579×0.8×16=0.3301 m³/class;

Poplar: V2=0.01679×0.8×59=0.7925m³/class

When L=1.27m,

Ash: V3=0.00999×0.8×23=0.1838 m³/class;

Color wood: V3=0.00999×0.8×23=0.1838 m³/class;

Basswood: V3=0.00999×0.8×23=0.1838 m³/class;

Poplar: V4=0.00599×0.8×87=0.4169 m³/class;

Total unutilized crushed material volume: V=0.7925+0.3301×3+0.4169+0.1838×3=2.7511m³/shift;

五. Calculate the amount of glue used:


1. The amount of rubber required per m³ of finished product Qgj

Qgj=[q(m-1)/Sj×Kj

q-----process consumption quota (take 300g/ m³ adhesive layer);

m----the number of plywood layers (m=3 and m=11);

Sj-------plywood thickness (Sj=3mm and Sj=11mm);

Kj------plywood processing coefficient;

Kj=Fw/Fj>1

Fw----unprocessed plywood area (Fw=1.27×2.51);

Fj------processed plywood area (Fj= 1.22×2.44);

Then Kj=3.1877/2.9768=1.07>1

The amount of glue required per m³ of finished three-layer plywood: Qgj=[300×(3-1)]/3×1.07=321 kg/m³;

The amount of rubber required per m³ of eleven-layer plywood finished products Qgj=[300×(11-1)]/11×1.07=291.8 kg/m³;

In the rubber consumption quota Q0, various production consumption should also be considered, then Q0= Qgj×f; In the formula: f takes 1.02;

Then the amount of rubber required for each m³ three-layer plywood finished product: Q0=321×1.02=327.42 kg/m³;

The amount of rubber required for each m³ of eleven-layer plywood finished products: Q0=291.8×1.02=297.65 kg/m³;

2. Calculation of annual glue requirement per shift:

Q class = Q'×Q0×η; where: Q'------productivity per shift, m³/shift;

η------Percentage of plywood;

5 plywood

Class Q=29.46×327. 42×60%=5787.48kg;

11 plywood

Class Q=29.46×297.65×40%=3507.51kg;

Year Q=C×t×Q class; in the formula: C-----the number of working shifts, take C=2;

t------Number of working shifts per year t=280;

5-ply plywood

Year Q=2×280×5787.48=3240.989 t

11 ply plywood

Year Q=2×280×3507.51=1964.204 t

Total demand Q= 5205.193 t

六. Main equipment requirements:

1. Veneer Manufacturing Equipment Calculation

(A). Cut sawing yield Q=60K×T×q/(t1+t2)×z

In the formula: t1------the time spent on each kerf, take 1.56s

t2------From one saw cut to the next saw cut, the log moving time, take 50s

z-------the sawing number of a log

K------Utilization coefficient of working hours per shift, take 0.7

T-------450min working time per shift

q-------a log volume m³

Choose KP---4 type circular saw machine

Q=60×0.7×450×0.83/40/4=98m³/class

Number of units: n=Q1/Q=64.692/98=0.6601 units, take 1 unit;

Load: η=0.6601/1=66.01%;

Saw body length: 1750mm:; the maximum diameter of sawing wood section: 1400mm;

Saw road width: 7mm; Motor power: 5.5kw

(B). Log debarker+Veneer peeling machine: 

veneer peeling machine with hydraulic knife holder

4feet wood debarker

Model: MH-WD4A

Max log length: 1400mm

Max log diameter: 550mm

Speed: 70m/min

Electric parts: Schneider

Roll type: electroplate(wear-resisting)

Total power: 29.5kw

Single roll motor:11kw

Double roll motor: 11kw

Hydraulic station: 7.5kw

Knife size: 1500*180*16mm

Weight: 4ton

Size: 3800*2300*1500mm

4feet veneer peeling machine

Model: MH-VPM4A

Max log length: 1400mm

Max log diameter: 500mm

Thickness: 0.5-4mm

Speed: 60m/min

Total power: 46.5kw

Single roll motor:7.5kw*2pcs

Double roll motor: 7.5kw*2pcs

Feeding motor: 11kw(servo motor)

Cutter motor: 4kw

Rubber roll motor: 1.5kw

Electric box: with air-conditioner for inside parts.

Weight: 7ton

Peeling knife size: 1500*180*16mm

Cutting knife size: 1500*90*12.7mm

Machine size: 4300*2300*1500mm


Promise: make sure the thickness accurate.

(C)Equipment selection and calculation of veneer dryer and veneer drying : 

Veneer drying

Productivity Q of mesh belt dryer (m³/shift)

Q=(T×n×m×s×b×L×K1× K2× K3)/(1000×z)

In the formula: T ----- working time per shift (s);

n-----Number of veneer sheets on the width of each layer, take n=3;

m----the number of layers, take m=5;

s------Veneer thickness 1.1mm;

b------Single board width 1.27m;

L------The working length of the dryer is 19m;

K1----take 0.95;

K2----take 0.98;

K3-----maneuvering time utilization coefficient, take 0.98;

Q=(450×3×5×1.1×1.27×19×0.95×0.98×0.98)/(1000×5.43)

=33.6m³/class

Choose MINGHUNG wood machinery factory MH-3840 mesh belt type veneer dryer, the technical parameters are as follows:

Machine layers 2 floors

Hot air system Heating area 15 sections x 2m = 26m

Cold air system Cold area 3 sections section×2m=6m

Feeding length Infeeding roller 4.5m

Infeed conveyor roller 2.67m

Outfeeding flat conveyor length Outfeeding flat conveyor 2.77m

Radiator 13pcs

Radiator size Radiator size 1850*870*35mm

Total power Total power 137.4KW (WANNAN motor)

Conveyor motor 5.5kw×1pcs=5.5kw

Heating blower motor 7.5kw×15pcs=112.5kw

Cooling fan motor 7.5kw*2pcs=15kw

Moisture removal motor 2.2kw*2pcs=4.4kw

Transmission motor The transmission speed 1-17m/min

Heating method Heating medium heat transfer oil or steam Oil /Steam

Drying temperature Drying temperature 120-170℃

Dry veneer thickness Veneer thickness 1.7-2.2mm

Initial moisture -60%

The end moisture %0-%10±1

Output Drying capacity 3-4m3/hour

External dimensionsMachine size 45.94*5.6*4.7m(L*W*H)

WeightWeight(about) 102ton

(D) Calculations for plywood manufacturing equipment:

1. Calculation and selection of gluing machine equipment:

The number of glue applicators is calculated by the following formula:

n=l×m/(t×π×d×n×K)

In the formula, l------the length of a middle plate (m);

m-------The number of middle plates that all presses need to glue in one pressing cycle (three layers

15 sheets, 55 sheets on the eleventh floor);

t-------one working cycle time of the press (7 minutes for the third floor, 30 minutes for the eleventh floor)

d-------diameter of gluing roller (m);

n-------gluing roller speed (r/min);

K------Glue utilization coefficient, take K=0.70;

Coating roller diameter: 300mm; blank size: maximum width: 2600mm

Coating roller line speed: 0.6m/s; Dimensions: 2800×1000mm;

Because 2π×r×n=v=35, so r=19.12r/min

Then the three-layer plywood n1=(2.51×15)/(7×3.14×19.12×0.3×0.7)=0.4266 units

Then eleven layers of plywood n2=(2.51×30)/(13×3.14×19.12×0.3×0.7)=0.4595 units

A total of n=0.886 units, take 1 unit,

Load percentage η=0.886/2×100%=88.6%

2700mm Glue machine:

glue spreader

Model: MH-GSM8

Roller length: 2700mm

Roller diameter:410mm

Power: 7.5kw

Weight: 7.5kw

Weight: 3500kg

Size: 3250*1250*1700mm

Use black rubber roll, good material

With the conveyor roll


2. The pre-press equipment is selected in the calculation:

pre press


Then the 6-layer plywood Q1=(0.96×480×100×3×1.27×2.49)/(1000×70) =6.24 m³/shift

11-layer plywood Q1=(0.96×480×100×11×1.27×2.49)/(1000×70)=23.52 m³/shift

n=Q total/(Q1×0.7+Q2×0.3)=29.46/(6.24×0.6+23.52×0.4)=2.24 sets

Load percentage η=2.24/3=74.7%

Choose 3 sets of C-400 pre-pressing machines, the technical parameters are as follows:

Total pressure: 420t; Allowable pressure on the working table: 12kg/cm²;

The maximum distance between the working table: 1300mm; Dimensions: 2580×1360mm;

Motor power: 10kw;

The productivity Q (m³/shift) of the pre-press is: Q=K×T×n×s×F/(1000×F total)

In the formula: T------working time per shift (min);

K ------ the working time utilization coefficient of the pre-pressing machine, take 0.96;

n-------The number of sheets of plywood slabs in one pressing, take 100 sheets;

s-------plywood thickness (three layers 3mm, eleven layers 11mm);

F ------ edge-aligned plywood format;

F------In a working cycle, the sum of the time consumed by each factor,Take 70min;

MINGHUNG 500ton Cold press machine

Model: MH-CP

Pressure: 500ton

Cylinder: φ360*2pcs

Length*width: 2700*1370mm

Upper beam thickness: 900mm

Bottom beam thickness: 900mm

Middle beam thickness: 400mm

Max opening: 1800mm

Min opening: 800mm

Motor brand: Siemens

Electric parts: Schneider

Weight: 13ton

Size: 3600*1370*4000mm

3. 

Hot press machine/sıcak pres makinesi

Model: MH-HP15

Pressure: 500ton

Cylinder: φ360*2pcs

Floors: 15(16pcs hot plates)

L*W of hot plates: 2700*1370*42mm

Upper beam thickness: 900mm

Bottom beam thickness: 900mm

Middle beam thickness: 400mm

Frame steel thickness: 35mm

Plates distance: 70mm

Power: 29.5kw

Motor brand: Siemens

PLC brand: Siemens

CNC screen: Siemens

Electric parts: Schneider

Size: 3600*1370*5000mm

Weight: 38ton


3.Selection and calculation of plywood trimming equipment:

plywood DD saw machine

Selection and calculation of double saw blade edge sawing machine:

Productivity A (sheet/shift) is: A=z×K1×K2×n/(2×L)

In the formula: z ----- working time per shift (min)

v-----approaching material speed (m/min), take the average planting of vertical and horizontal feeding speed;

K1--working time utilization coefficient, take 0.91;

K2 - maneuvering time utilization coefficient, take 0.85;

n----the number of sheets of each plywood;

L----the length L (m) of the cut plywood, take the average length and width;

Choose MINGHUNG MH-DD edge sawing machine, the main technical parameters are as follows:

Maximum processing width: vertical 900-1530mm; horizontal 1550-2550mm;

Processing maximum thickness: 38mm;

Feeding speed: longitudinal: 9m/min; transverse: 8m/min;

Dimensions: 9255×7340mm;

Then A=450×8.5×0.91×0.85×4/[2×(2.51/2+1.27/2)]=3147.18 sheets/class

In actual production, the number of sheets of plywood produced per hour is required to be n=266 sheets/h

The number of units needed is n=266×8/3147.18=0.6762 units, take 1 unit,

Load percentage η=0.6762/1×100%=67.6%

MINGHUNG Plywood saw machine

Model: MH-DD

Length: 8feet

Width: 4feet

Working speed: 40-70m/min

Saw blade size: 305mm

Capacity: 4-6pcs/min

Working style: infrared guide

With one set lift table for stacking

Size: 9000*6000*1300mm

Weight: 6ton

4. Selection and calculation of sanding machine equipment: 

plywood sanding machine (2)

Productivity of double-sided sander (sheets/shift)

A=z×v×K1×K2/(2×L)

In the formula: z ----- machine tool working time (min);

Calculation process and description

v-----feed speed 16m/min,;

K1-----enrichment coefficient of the machine tool, take 0.9

K2-----Working time utilization coefficient, take 0.96;

L ------ The plywood of the feed sander is 15° from the grinding angle

Choose MINGHUNG MH-SD1213 model sander, the technical parameters are as follows:

Working width: 1830mm; Working thickness: 3-20mm;

Abrasive belt quantity: 2 pieces; Abrasive belt length: 2.6m; Feeding speed: 25m/s;

Dimensions: 3200×3700×2800mm;

Then A=(480×16×0.9×0.96)/(2×1.1784)=2815.48 sheets/class

The number of units needed is n=266x8/2815.48=0.7559 units, take 1 unit

Load percentage η=0.7559/1×100%=75.6%


More about plywood making processing contact us: 

Whatsapp: +8618769900191  +8615589105786   +8615805493072

Website: www.plywoodmachineline.com 

Email: minghungmachinery@gmail.com 








Shandong MINGHUNG Wood Machinery Co.,Ltd is one famous manufacturer of plywood machine in China, located in Linyi city. 

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